PENILAIAN TENGAH SEMESTER (PTS)
Nama : Regita
Kelas : X MIPA 3
ā =[1], b= [5], dan c=[4], maka hasil dari
2 4 -1
3 -1 1
Operasi vektor ā + 2b - 3c adalah...
DIK = •a = (1 2 3 )
•b = (5 4 -1)
•c = (4 -1 1)
Dit : vektor ā + 2b - 3c
Jawab :
a + 2b - 3c
= [ 1 ] [ 5 ] [ 4 ]
2 + 2 4 - 3 -1
3 -1 1
[ 1 ] [ 10 ] [ 12 ]
= 2 + 8 - -3
3 -2 3
= [ 1 + 10 - 12 ]
2 + 8 - (-3)
3 +(-2) -3
= [ -1 ]
13 (D)
-2
= -i + 13j - 2k
2. Diketahui |ā| = √3 , |b| = 1 dan |ā - b|= 1. Panjang vektor ā+b adalah...
|ā+b| = 2(|ā|^2 + |b|^2 - |ā-b|^2
= 2((2√3)^2 + 1^2) - 1^2
= 2.(3 + 1) - 1 = 7
|ā+b| =√7 (c)
3. Diketahui ā =2i - 3j + 4k dan b = 5j+5k. Nilai ā.b adalah...
Jawab :
ā.b = x1 x2 + y1 y2 + Z1 Z2
= 2× 0 + (-3) × 5 + 4 × 5
= 0 - 15 + 20
= 5 (b)
4. Diketahui (ā+b)^2 =(ā)^2 + (b)^2 + 2ā.b
=|ā|^2 +|b|^2 + 2|ā||b|cos











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